cancel
Showing results for 
Search instead for 
Did you mean: 

PSoC 4

joli_601446
Contributor

Hello, I'm using the PSOC4 4200 to sequence the power rails for an FPGA. I would like to run the PSOC in Unregulated External Supply to I can only provide 5V to the device. The 5V is applied as soon as power is applied to the board.

Is this the correct configuration for the 28-SSOP CY8C4244PVI-442?

PSOC4_4200_PROG_HEADER.jpg

Thank you very much,

Joe

0 Likes
1 Solution
NoriakiT_91
Employee

Please refer the datasheet.

PSoC® 4: PSoC 4200 Family Datasheet

Document Number: 001-87197

There is a power supply example schematic

GS004512.png

and a table describing the required bypass-capacitors for TQFP package.

GS004513.png

View solution in original post

0 Likes
4 Replies
NoriakiT_91
Employee

Please refer the datasheet.

PSoC® 4: PSoC 4200 Family Datasheet

Document Number: 001-87197

There is a power supply example schematic

GS004512.png

and a table describing the required bypass-capacitors for TQFP package.

GS004513.png

View solution in original post

0 Likes
joli_601446
Contributor

Hello, thank you for responding to my message. The example schematic is confusing, what symbol is ground and what symbol is for power? Is VSS the symbol for ground?

The data sheet says pin 28 is ground which I have connected to and it also says pin 26 could be tied to ground through a cap. I also read that it says to short VCCD to VDD. I'm confusing myself.

Can you please help clarify things for me.

Respectfully,

Joe

0 Likes
NoriakiT_91
Employee

The example schematic is describing about the bypass capacitor only.

If you want to supply 5V only, connect the power line to the VDD.

GS004514.png

In the TSSOP28 package, VDDD and VDDA are tied together to the VDDD pin.

The VCCD pin has two function.  When the internal regulator is used, VCCD pin is used to connect a bypass capacitor for the internal 1.8V regulator.  When the internal regulator is not used, VCCD pin is used as a power supply pin from an external power supply.

In your case providing 5V to VDDD, it is enough to connect a 1uF ceramic bypass capacitor to the VCCD pin.

0 Likes
joli_601446
Contributor

Great! So the schematic that I uploaded is correct for a 5V only supply?

Joe

0 Likes