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Hi all,
Could you tell me about the power loss of both TT60N16SOF and TT175N16SOF?
I think that "On-state power loss per arm PTAV = f (ITAV)" described in the data sheet is the condition of frequency 50 / 60Hz.
Do you have this data at 400Hz?
Their application is a three-phase thyristor rectifier.
Best regards,
MS
Solved! Go to Solution.
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Hi MS_19060803,
Thanks for posting in Infineon Community page.
The On state losses for
- TT175N16SOF
VT0 = 0.83 V
rT = 1.3 mΩ
ITAV = 20 A
ITRMS = 34.6 A
PTAV = VT0 • ITAV + rT • I²TRMS
PTAV = (0.83 * 20) + (1.3 * 10^-3 * 34.6 *34.6)
PTAV = 18.156 W
- TT60N16SOF
VT0 = 1 V
rT = 4.8 mΩ
ITAV = 6.7 A
ITRMS = 11.5 A
PTAV = VT0 • ITAV + rT • I²TRMS
PTAV = (1 * 6.7) + (4.8 * 10^-3 * 11.5 *11.5)
PTAV = 7.335 W
To calculate the Reverse recovery losses, use the below formula
E𝑟𝑒𝑐 = 0.5 × 𝑉𝑅𝑝𝑒𝑎𝑘 × 𝑄rr
𝑉𝑅𝑝𝑒𝑎𝑘 = Peak Reverse Recovery Voltage
𝑄rr = Reverse recovery charge
𝑄rr depends on the di/dt, which can be selected from the 𝑄rr vs di/dt graph (Recovered charge Qr = f(-di/dt))
Prec = E𝑟𝑒𝑐 * Frequency
Refer the below images 𝑄rr vs di/dt graphs from the data sheets
Total Power Loss = PTAV + Prec
Best Regards,
Akhil Kumar
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Hello,
Thank you for posting on Infineon Community.
On-State Power loss PTAV is a function of ITAV and conduction angle and does not vary with frequency as shown in datasheet. One can use the given data for any frequency for average on-state losses.
The average value of the on-state loss PTAV Is calculated according to the following formula:
PTAV = VT(TO) • ITAV + rT • I²TRMS
where,
ITAV : Mean Value of On-State Current
rT : On-State Resistance
VT(TO) : Threshold Voltage
ITRMS: R.M.S value of On-State Current
For total power loss calculations, please let me know about the current and voltage ratings required in your application.
Thanks and Regards,
Anshika
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Hi,
The current and voltage are as follows.
1.TT175N16SOF
ITAV = 20A
ITRMS = 34.6A
V = 250Vac (RMS value of AC input voltage)
2.TT60N16SOF
ITAV = 6.7A
ITRMS = 11.5A
V = 250Vac (RMS value of AC input voltage)
Best regards,
MS
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Hi MS_19060803,
Thanks for posting in Infineon Community page.
The On state losses for
- TT175N16SOF
VT0 = 0.83 V
rT = 1.3 mΩ
ITAV = 20 A
ITRMS = 34.6 A
PTAV = VT0 • ITAV + rT • I²TRMS
PTAV = (0.83 * 20) + (1.3 * 10^-3 * 34.6 *34.6)
PTAV = 18.156 W
- TT60N16SOF
VT0 = 1 V
rT = 4.8 mΩ
ITAV = 6.7 A
ITRMS = 11.5 A
PTAV = VT0 • ITAV + rT • I²TRMS
PTAV = (1 * 6.7) + (4.8 * 10^-3 * 11.5 *11.5)
PTAV = 7.335 W
To calculate the Reverse recovery losses, use the below formula
E𝑟𝑒𝑐 = 0.5 × 𝑉𝑅𝑝𝑒𝑎𝑘 × 𝑄rr
𝑉𝑅𝑝𝑒𝑎𝑘 = Peak Reverse Recovery Voltage
𝑄rr = Reverse recovery charge
𝑄rr depends on the di/dt, which can be selected from the 𝑄rr vs di/dt graph (Recovered charge Qr = f(-di/dt))
Prec = E𝑟𝑒𝑐 * Frequency
Refer the below images 𝑄rr vs di/dt graphs from the data sheets
Total Power Loss = PTAV + Prec
Best Regards,
Akhil Kumar