TraveoII Capture TR Function

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chme_4646286
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Level 4
Distributor - Intron(GC)
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请教一个TCPWM Capture输入配置的问题;

基于CYT2B7系列,我需要一个把P6.0和P6.1配置为外部capture输入,参考datasheet,其ACT#3和ACT#2支持;

chme_4646286_0-1638243011251.png

那我在代码编写中要如何选用对应的tr_one_cnt_in[nnumber]呢?

在SDL 头文件中P6.0和P6.1定义的tr_one_cnt_in[],为什么会有两种呢?二者之间的关系是?

chme_4646286_1-1638243147861.png

 

 

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yanf
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50 replies posted 50 sign-ins 25 solutions authored

Hi chme_4646286

TR_ONE_CNT_IN的序列号算法请参考SDL capture的例程

TR_ONE_CNT_INx: x = (256 * GrpNum * 3) + (CntNum * 3) + TR_ONE_CNT_NR_USE

然后将HSIOM根据算出来的结果配置为对应值。

Best Regards,

Finn

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yanf
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50 replies posted 50 sign-ins 25 solutions authored

Hi chme_4646286

TR_ONE_CNT_IN的序列号算法请参考SDL capture的例程

TR_ONE_CNT_INx: x = (256 * GrpNum * 3) + (CntNum * 3) + TR_ONE_CNT_NR_USE

然后将HSIOM根据算出来的结果配置为对应值。

Best Regards,

Finn

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chme_4646286
Level 4
Level 4
Distributor - Intron(GC)
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Hi yanf;

示例中TR_ONE_CNT_NR_USE是一个宏定义;

#define TR_ONE_CNT_NR_USE 0ul // from 0 to 2

这里定义的原则是什么?要怎么和TRM手册中说明对应起来?

 

 

 

 

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yanf
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50 replies posted 50 sign-ins 25 solutions authored

Hi chme_4646286

这是Input Trigger的序号,SDL库的代码可以在AN中找到解释。具体到这段代码,可以在AN220224的2.2.2节的Table 5中找到

Best Regards,

Finn

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