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Hi everyone
Regarding BGT60TR13C, I found out how to calculate the distance resolution from "Radar SDK Documentation",
but I have not found the description of angular resolution.
Could you tell me how to calculate the angular resolution?
Thanks
Yang
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Hi, YoJa_3107936
That's fine. This is the example about how to calculate the theoretical angular resolution of BGT60RT13C.
As shown in the picture, Rx1 and Rx3 & Rx2 and Rx3 forming a "L" shape array, and can detect angle from two directions with same angular resolution calculation method.
λ = 1/f = 1/(60GHz) = 5mm;
d = 2.5mm;
N = 2.
So, the angular resolution changes with the angle of object as following:
Hope that will help you,
Neo Lu
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Hi, YoJa_3107936
Thank you for your question.
As shown in the picture, to realize the measurement of AoA(angle of arrival), we need at least 2 RX antennas.
Considering that the distance between the target object and the sensor is much larger than the distance between antennas, we can approximate that the beams arriving at the two antennas are parallel, so the azimuth of the beams can be calculated as:
α:"angle of arrival, " ∆φ": phase deviation", λ:"max wavelength," d": antenna spacing".
When we talk about the angular resolution, we should know that we detect the angle by measure the "phase deviation". In other words, the angular resolution depends on the measuring resolution of "phase deviation".
Finally, the angular resolution can be calculated as:
Hope that will help you,
Neo Lu
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Hi Neo
Thank you for your advice!
Could you tell me how to calculate the angular resolution
when the three antennas R1, R2, and R3 are L-shaped?
Thanks
Yang
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Hi, YoJa_3107936
That's fine. This is the example about how to calculate the theoretical angular resolution of BGT60RT13C.
As shown in the picture, Rx1 and Rx3 & Rx2 and Rx3 forming a "L" shape array, and can detect angle from two directions with same angular resolution calculation method.
λ = 1/f = 1/(60GHz) = 5mm;
d = 2.5mm;
N = 2.
So, the angular resolution changes with the angle of object as following:
Hope that will help you,
Neo Lu
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Hi Lu
Thank you for your answer.
Thanks
Yang