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I need to get out of a problem in a hurry. I need to route an analogue signal out to another pin.
I am using a CY8C5888AXI-LP096. P4[0..5] route to a mux that feeds the DS ADC. The mux is in a sequencer that samples each of the six channels sequentially. I want to route one of these signals out to another pin.
I have reserved the six lines using Mux Constraints which leaves the global bus available. I close the switches on the route to my pin by writing to the various registers.
It sort-of works but only when the ADC mux channel is closed. It is as if the pin is disconnected from both buses.
My question: why does opening the analogue mux bus open the analogue global?
Solved! Go to Solution.
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Hello, Len,
Following on my previous reply, I have managed to DMA to the registers without opening the other switches.
I have attached a breadboard project that uses the CY8CKIT-059. I can't help feeling that there must be a ready-made component to do the same thing.
- Richard.