What can happen if CY8C4045LQI-S411 pin5&6 connect to 5V or GND by 0R resistor?

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zhaox
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Will the chip be damaged?

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LinglingG_46
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1:I2C interface has two lines: clock and data.

2:    If the chip act as an I2C slave, the clock pin drives high, it equally that the vdd connect to gnd.

3:    If the chip acts as an I2C master, it is the same as point2.

4:   I think if you design a system like this, so nothing should be surprised.

5:  It is suggested that you can change your design. At the same time the I2C resistor should be in the range of (2.2k-10k).

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LinglingG_46
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 When the chip was powered, the GPIO default status is "Analog High Z", in this case, the chip will have no any  influence if pin5&6 connect to 5v or GND ,but if you configure the pin to "strong" drive, and connect the pin to GND, the chip will be damaged.

Can you clarify the reason you design like this?

 

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zhaox
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Thank you!

They are IIC address selection pins in the design, but someone  installed 0 ohm to R42&R44. 

someone installed 0 ohm to R45&R46. 

After I programmed, the error I found through miniprog3 I2C

1. can not find device  , 

2.all or part of sensors short to GND

3. Some boards I can not program again

zhaox_1-1628666911672.png

 

 

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LinglingG_46
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500 solutions authored 1000 replies posted 10 questions asked

1:I2C interface has two lines: clock and data.

2:    If the chip act as an I2C slave, the clock pin drives high, it equally that the vdd connect to gnd.

3:    If the chip acts as an I2C master, it is the same as point2.

4:   I think if you design a system like this, so nothing should be surprised.

5:  It is suggested that you can change your design. At the same time the I2C resistor should be in the range of (2.2k-10k).

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zhaox
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Thank you!

Pin5&6 are only for address, not IIC, IIC are pin15&16 see below drawing, any mistake please tell me.

zhaox_0-1628669414105.png

 

 

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LinglingG_46
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Why do you design to connect pull down resistors in these two pins? I don't understand?

In addition, what do you mean the I2C address?  

If it is a digital input, just need to configure it as "Digital High Z".

Or could you tell me the reason to connect like this, I think before you design, you have had a deep analysis on this.

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Dear Lingling,

          we can close this issue now, thanks alot for the help!

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