Announcements

Webinar: Integrated solutions for smaller, simpler low-voltage motor control design.
Join the webinar to experience!

Tip / Sign in to post questions, reply, level up, and achieve exciting badges. Know more

cross mob
Kathisai
Level 1
Level 1
5 questions asked 10 sign-ins First reply posted

Hi team,

I am working on the TLE9879QXA40, My requirement is to access the entire ROM, I found the ROM size as below:

Kathisai_0-1693473584521.png

But when I try to access the ROM above the address 0x1101F000, I can't read the data above the ROM address 0x1101F000 because the in keil target options the ROM size is 0x1EFFC (starting address of ROM i.e., 0x11000000 + 0x1EFF= 0x1101F000)

as below and facing an error 

 

Kathisai_2-1693474318561.png

Error when tried to read the data above the address 0x1101F000:

Kathisai_4-1693476991017.png

 

But when I try to increase the ROM size in target options of keil I am facing an error as below:

Kathisai_3-1693474439332.png

My query is how can I read the data of ROM (flash) above the address of 0x1101F000.

 

0 Likes
1 Solution
Raj_C
Moderator
Moderator
Moderator
500 replies posted 50 likes received 250 replies posted

Hi @Kathisai,

The TLE9879QXA40 has a 128 kBytes of ROM(FLASH). It's range can be seen in the following snippet:

Raj_JC_0-1693480117901.png

 

For flash size of different devices please refer to the Table 1 and Table 2 from TLE987x User Manual.

 

Please let us know if you have further questions.

 

Thank you

Best Regards

Raj Chaudhari

View solution in original post

0 Likes
2 Replies
Raj_C
Moderator
Moderator
Moderator
500 replies posted 50 likes received 250 replies posted

Hi @Kathisai,

The TLE9879QXA40 has a 128 kBytes of ROM(FLASH). It's range can be seen in the following snippet:

Raj_JC_0-1693480117901.png

 

For flash size of different devices please refer to the Table 1 and Table 2 from TLE987x User Manual.

 

Please let us know if you have further questions.

 

Thank you

Best Regards

Raj Chaudhari

0 Likes
Kathisai
Level 1
Level 1
5 questions asked 10 sign-ins First reply posted

Thanks for the quick response.

0 Likes