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Hello,
Please tell me about CY2DL1510AZC's junction temperature: Tj and package thermal resistance: Θjc.
Best Regards,
Naoaki Morimoto
Solved! Go to Solution.
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Hi Morimoto-san,
The maximum junction temperature of CY2DL1510AZC is 135°C.
And you can find the thermal resistance of CY2DL1510AZC in the datasheet:
If you want to calculate the operating junction temperature, you could use the following formula:
Tj = TA + (ƟJA)×(Pd)
Where,
ƟJA = Junction-to-ambient thermal resistance (Theta JA).
TA = Ambient operating temperature (temperature grade of the actual device)
Pd = Voltage (V) × Current (I). Typical Voltage and Current values are found in the datasheet
For example, when TA = 55°C, operating voltage V=2.5V, operating current I= 50mA,
then Tj = 55 + 69 x (2.5 x 0.05) = 63.625 °C
You can find more details in KBA220732 and AN201006.
Best regards,
Shuping
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Hi Morimoto-san,
The maximum junction temperature of CY2DL1510AZC is 135°C.
And you can find the thermal resistance of CY2DL1510AZC in the datasheet:
If you want to calculate the operating junction temperature, you could use the following formula:
Tj = TA + (ƟJA)×(Pd)
Where,
ƟJA = Junction-to-ambient thermal resistance (Theta JA).
TA = Ambient operating temperature (temperature grade of the actual device)
Pd = Voltage (V) × Current (I). Typical Voltage and Current values are found in the datasheet
For example, when TA = 55°C, operating voltage V=2.5V, operating current I= 50mA,
then Tj = 55 + 69 x (2.5 x 0.05) = 63.625 °C
You can find more details in KBA220732 and AN201006.
Best regards,
Shuping
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Hello Shuping-san,
Thank you for your answer.
My question has been solved.
Best Regards,
Naoaki Morimoto