About SIG certification with EZ-Serial F/W

[KeTa_1341526]

Hello,

I would like to confirm SIG certification for a system with a CYBT-343026-01 Module programmed with EZ-Serial F/W.

Should I register only the QDID of the Module when performing SIG certification for the end product?

In the thread below, it is commented that EZ-Serial F/W supports BT4.2.

Module is 5.0 and stack is supposed to be 4.2, is this a problem?

If there is a problem, does it need to be registered with 4.2 as an End product?

If yes, how should I register with BT SIG?

Thanks

[Sven_Wang]

Hi @KeTa_1341526 

About how to register with BT SIG, please refer to this link:
https://launchstudio.bluetooth.com/

I believe if the certification is 5.0, but the features are 4.2, you should still use the 4.2 part of the newest certification.

Thanks

Sven

[KeTa_1341526]

Hi Sven-san,

Thank you for your reply.

Please let me confirm a little more.

CYBT-343026-01 has two QDIDs.

99198 - End Product

164447 - End Product

The designs combined into each End Product are as follows.

99198 - End Product

- 72771 - Component : BTE WICED (Core Spec 4.2)

- 104467 - Component : CYW20703/CYW20704/CYW20706/CYW20707/CYW20734 (Core Spec 5.0)

164447 - End Product

- 115853 - Component : CY-WICED 4.0 BLUETOOTH Host Software Stack (Core Spec 5.0)

　* Combined 72771 : BTE WICED (Core Spec 4.2):

- 159590 - Component : CYW20707/CYW20706/CYW20703/CYW20704/CYW20734 (Core Spec 5.2)

- 101726 - Component : CYW-MESH 1.0

Since the core spec of BTE WICED is 4.2, when registering the End Product with a module that uses EZ-Serial, I think that there is no problem in registering the End Product with "99198" or "164447".

Do you recognize each other?

Also, when registering a final product with a custom F/W that uses the latest BT SDK (AIROC™ Bluetooth Host Software Stack 4.3 [QDID:196979]), should I register "196979" together with "99198" or "164447"?

Thanks

[Sven_Wang · Accepted solution]

Hi Keta,

Yes, there have two QDIDs for the end product. But I think you just need to register the newest(164447).

Thanks

Sven